Question

show that a given gun will shoot three times as high when elevated at an angle of 60°as compared with foring at an angle of 30°​

Answer 1

Max height of projectile is given by

H = u²sin²Ɵ/2g

projectile with angle 30° is H1

and with 60° is H2

H1/H2 = u²sin²(30)g/u²sin²(60)g

H1/H2 = (1/4)/(3/4)

H1/H2 = 1/3

H2 = 3H1