Question

Show that a linear S.H.M. is the
projection of a U.C.M. along any of its
diameter.
​

Answer 1

the projection of its motion along any diameter of its path executes S.H.M. Consider particle 'P' is moving along the circumference of circle of radius 'a' with constant angular speed of ω in anticlockwise direction as shown in figure. ... hence S.H.M. is projection of U.C.M. along a diameter, of circle.

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