Question

show that a minus b, a and a + b form consecutive term of an ap​

Answer 1

We already know that term of an AP have same difference or have common difference .

AP: a-b ,a ,a+b

Here a1 = a-b

a2 = a

a3 = a+b

Common difference = a2-a1

=a-(a-b)

=a-a+b

=b

Similarly when we subtract a2 from a3 we get b

So a-b,a,a+b is in ap with common difference of b.

Answer 2

To show : a-b, a , a+b are continuous terms of an ap