Question

show that a minus b into a + b + b minus C into B + C + c minus A into C + A = 0​

Answer 1

Step-by-step explanation:

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)

=a²+ab-ab-b²+b²+bc-bc-c²+c²+ac-ac-a²

=a²-a²+b²-b²+c²-c²+ab-ab+bc-bc+ac-ac

=0.

Answer 2

Answer:

its provded that its = 0

please like my answer