Show that a pair of linear equations 7x+y=10 & x+7y=10 are consistent
Answers
Answered by
52
Hi !
7x + y = 10
x + 7y = 10
For a pair of linear equations to be consistent , it must have :-
1)Either one unique solution
OR
2)Infinitely many solutions
We can check whether the given pair of equations have infinitely many solutions or unique solutions , by examining their coefficients !
7x + y = 10
7x + y - 10 = 0
a₁ = 7 , b₁ = 1 , c₁= -10
x + 7y = 10
x + 7y - 10 = 0
a₂ = 1 , b₂ = 7 , c₂ = -10
For a pair of linear equations to have unique solutions :-
a₁/a₂ ≠ b₁/b₂
Lets check whether the condition is true , if its is true , then the equations would have unique solutions , and therefore it would be consistent.
7/1 ≠ 1/7
This condition is true !
Hence , the given pair of linear equations has unique solution !
Hence , they are consistent !
7x + y = 10
x + 7y = 10
For a pair of linear equations to be consistent , it must have :-
1)Either one unique solution
OR
2)Infinitely many solutions
We can check whether the given pair of equations have infinitely many solutions or unique solutions , by examining their coefficients !
7x + y = 10
7x + y - 10 = 0
a₁ = 7 , b₁ = 1 , c₁= -10
x + 7y = 10
x + 7y - 10 = 0
a₂ = 1 , b₂ = 7 , c₂ = -10
For a pair of linear equations to have unique solutions :-
a₁/a₂ ≠ b₁/b₂
Lets check whether the condition is true , if its is true , then the equations would have unique solutions , and therefore it would be consistent.
7/1 ≠ 1/7
This condition is true !
Hence , the given pair of linear equations has unique solution !
Hence , they are consistent !
Answered by
46
Hey there!
The two linear equations are
7x+y=10 => 7x+y-10=0
x +7y =10 => x+7y-10=0
Here
a1=7, b1 = 1,c1=-10
a2=1, b2=7, c2=-10
So
Here
7/1≠1/7
a1/a2≠ b1/b2
The system is consistent & have unique solution.
Hope helped!
The two linear equations are
7x+y=10 => 7x+y-10=0
x +7y =10 => x+7y-10=0
Here
a1=7, b1 = 1,c1=-10
a2=1, b2=7, c2=-10
So
Here
7/1≠1/7
a1/a2≠ b1/b2
The system is consistent & have unique solution.
Hope helped!
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