Question

Show that a triangle with sides n² + 1,n² + 1 and 2n, contains a right angle.​

Answer 1

Step-by-step explanation:

given sides of the triangle

n²+1 , n²+1 ,2n

here we can apply Pythagoras theorm

since the hypotenuse is the largest side in a right angled triangle, and n²+1 is the length of two sides

n²+1 can't be the hypotenuse

so hypotenuse is 2n

hence, (2n)² = (n²+1)² + (n²+1)²

$2n = \sqrt{2 {( {n}^{2} + 1 )}^{2} }$

$\sqrt{2} {n}^{2} + \sqrt{2} - 2n = 0$

Answer 2

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