Show that a1, a2, a3..........an,......form an AP where an is defined as an = 3 + 4n Also find the sum of
first 10 terms.
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Answer:
an = 3 + 4n
n = 1
a1 = 3 + 4 = 7
n = 2
a2 = 3 + 8 = 11
n = 3
a3 = 3 + 12 = 15
d = a2 - a1 = a3 - a2
d = 11 - 7 = 15 -11
d = 4 = 4
Hence it forms an AP.
S10 = 10/2( 2*7 + 9*4 )
S10 = 5( 14 + 36 )
S10 = 250
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