Show that Σab(a + b) + 2abc = (a + b) (b + c) (c + a) pls, answer fast and serious answers only!
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By performing R1 aR1, R2 bR2, R3 cR3 and dividing the determinant by abc, we get
Now, taking a, b, c common from C1,C2 and C3
Applying C1C1 - C2 C2 C2 - C3
Applying R3 R3- (R1 + R2)
Applying C1 C1
hope it helps you
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