Math, asked by krishtinapegu2, 3 days ago

show that ab/(b-c)(c-a) + bc/(a-b)(c-a) + ca/(a-b)(b-c)=-1

Answers

Answered by XxcupcakexX22

0

Answer:

ab−bc,bc−ca,ca−ab

Adding we get,

ab−bc+bc−ca+ca−ab

=0

Step-by-step explanation:

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