Question

show that AB||EF
pls ans fast​

Answer 1

angle a =57

angle c=22+35=57

since alternate interior angles are equal AB||CD

angle e=145

angle dce =35

angle e + angle dce=145+35=180 (corresponding angles are supplementary)

So CD||EF

Since CD is already parallel to AB, AB also parallel to EF ie, AB||EF

Answer 2

Answer:

AB||BF, AC is common, AB||CD, CD||BF, so it's proved, AB||BF