Question

show that ab is parallel to ef b= 70°, angle BCE = 30° , angle BCD = 40° , angle = 140°​

Answer 1

please give diagram(figure) of question

Answer 2

Answer:

See the diagram in attachment

${ \huge{ \underline{ \bf{ \red{Given}}}}}$

B=70 , BCD=40 , BCE = 30, E = 140

Find :- AB || EF

Solution :-

Angle AB = 70

Angle BCD = Angle BCE + Angle ECD = 40+30=70

So, They are alternative angles

Therefore,AB||CD......(1)

Angle ECD,CEF are co-interior angles

Angle ECD+CEF=180

EF||CD........(2)

${ \to{ \sf{From \: (1) \: and \: (2)}}}$

${ \to{ \sf{AB\: ||\:CD = CD\: || \: EF }}}$

${ \to{ \sf{AB \: ||\: { \cancel{CD}} = { \cancel{CD}} \: || \: EF}}}$

${ \to{ \sf{AB = EF}}}$

${ \therefore{ \sf{AB = EF}}}$

Hence proved ✔︎