Question

show that ∆ABC , where A (22,0),B(2,0) , C(0,2) , and ∆PQR where P(-4,0),Q(4,0),R(0,4) are similar triangle.​

Answer 1

Answer:

HEY THERE!

Here, ABC is a triangle having vertices A (22, 0) B(2, 0) and C(0 , 2),

And, PQR is also a triangle having vertices P(-4,0) Q(4,0) and R(0,4),

By the distance formula,

AB=√(2-22)²+(0-0)²=√20²=20

Similarly,

BC=2√2

CA=2√122

PQ= 8

QR=4√2

RP=4√2

20/8 ≠ 2√2/16√2 ≠ 2√122/4√2

==AB/PQ≠BC/QR≠CA/RP

Hence, triangles ABC and PQR are not similar.