Physics, asked by anchal8980, 4 months ago

show that acceleration at any instant does not depends upon the velocity at that instant

Answers

Answered by ItsManipulator
0

Given :

Heat gained = 4.5 × 10⁵ J

Heat released = 2 × 10⁵ J

To Find :

Percentage efficiency of steam engine and work done per cycle..

Solution :

❒ Efficiency of a heat engine/steam engine is given by, η = 1 - (Q₂ / Q₁)

Where,

η denotes efficiency

Q₂ denotes heat released to the sink

Q₁ denotes heat extracted from the source

By substituting the given values;

➛ η = 1 - (Q₂ / Q₁)

➛ η = 1 - (2 × 10⁵ / 4.5 × 10⁵)

➛ η = 1 - 0.44

➛ η = 0.56

Percentage efficiency = 56%

❒ Work done per cycle :

We know that work done is measured as the change in energy.

➠ W = Q₁ - Q₂

➠ W = (4.5 × 10⁵) - (2 × 10⁵)

➠ W = 2.5 × 10⁵ J

Answered by Sahasravedala007
0

Answer:

Consider this:

If an object is moving at 1 m/s and accelerates to 2 m/s over the course of one second, its acceleration is 1 m/s².

Similarly if an object is moving at 1000 m/s, and accelerates to 1001 m/s over the course of one second, its acceleration is also 1 m/s².

The acceleration does not depend upon velocity. Simply put, it depends on two things: the amount of change in the velocity, and how long it takes to change. In both cases above, the change in velocity, or  Δv , (pronounced “delta vee”) is one meter per second, and in both cases it took one second to do so. And 1 m/s over 1 s is 1 m/s².

Less simply put, the acceleration is the first derivative of the velocity, which requires differential calculus to calculate, but it has the advantage of being able to give you a value for instantaneous acceleration without threatening your calculations with the ignominy of a division by zero. But acceleration remains independent of velocity for essentially the same reason.

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