Question

Show that AE=ED................​

Answer 1

Answer:

in figure only it is shown

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Answer 2

Step-by-step explanation:

Given,

Angle DBC = ABC {Shown}, hence, EBC is an isosceles triangle as an isosceles triangle has its base angles equal.

Angle ABD+DBC = DCA+ACB {Shown},

Side BC = BC {Common Base},

Angle DBC = ACB {Shown},

So, by ASA congruence criterion, Triangle ABC is congruent to Triangle DCB.

Hence, AC = BD {As both triangle are congruent},

EC = EB {Equal sides of isosceles triangle EBC},

AC - EC = BD - EB,

→AE = DE.

Hence, we get, AE = DE.

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