Question

Show that all natural numbers more than one: m²+1, 2m, m²-1
can form Pythagorean triplets.
Need proper answer with whole solution.
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Answer 1

Answer:

10th

Maths

Triangles

Pythagoras Theorem and its Converse

Show that (m^2 - 1), (2m), ...

MATHS

Show that (m

2

−1),(2m),m

2

+1 always form a pythagoran triplet.

MEDIUM

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ANSWER

Let a=m

2

−1

b=2m

c=m

2

+1

using pythagoras theorem, a

2

+b

2

=c

2

So, (m

2

−1)

2

+4m

2

=(m

2

+1)

2

m

4

+1−2m

2

+4m

2

=(m

2

+1)

2

m

4

+2m

2

+1=(m

2

+1)

2

(m

2

+1)

2

=(m

2

+1)

2

Since LHS=RHS , we can say that a,b,c always form pythagorean triplet.

Answer 2

Answer:

hope this would help

Step-by-step explanation:

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