Question

show that an even integer is of form 6q or 6q +2 or 6q + 4 whare q is positive integer

Answer 1

Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️

Let ‘a’ be any positive even integer and ‘b= 6’.

Therefore, a = 6q +r, where 0 ≤ r < 6.

Now, by placing r = 0, we get, a = 6q + 0 = 6q

By placing r = 1, we get, a = 6q +1

By placing, r = 2, we get, a = 6q + 2

By placing, r = 3, we get, a = 6q + 3

By placing, r = 4, we get, a = 6q + 4

By placing, r = 5, we get, a = 6q +5

Thus, a = 6q or, 6q +1 or, 6q + 2 or, 6q + 3 or, 6q + 4 or, 6q +5.

But here, 6q +1, 6q + 3, 6q +5 are the odd integers.

Therefore, 6q or, 6q + 2 or, 6q + 4 are the forms of any integer

Answer 2

Let ‘a’ be any positive even integer and ‘b= 6’.

and r=0,1,2,3,4,5,6.

Therefore, a = 6q +r, where 0 ≤ r < 6.

Now, by placing r = 0, we get, a = 6q + 0 = 6q

By placing r = 1, we get, a = 6q +1

By placing, r = 2, we get, a = 6q + 2

By placing, r = 3, we get, a = 6q + 3

By placing, r = 4, we get, a = 6q + 4

By placing, r = 5, we get, a = 6q +5

Thus, a = 6q or, 6q +1 or, 6q + 2 or, 6q + 3 or, 6q + 4 or, 6q +5.

But here, 6q +1, 6q + 3, 6q +5 are the odd integers.[so they are rejected]

Therefore, 6q or, 6q + 2 or, 6q + 4 are the forms of any integer