Question

show that an isosceles triangle angles opposite to equal sides are equal​

Answer 1

Proof: we are given an isosceles triangle ABC in which AB=AC . WE need to prove that <A = <C

Let us draw the bisector of <A and let D be the point of intersection of this bisector of <A and BC (SEE FIGURE)

In triangle BAD and triangle CAD,

AB=AC (GIVEN)

<BAD=<CAD (BY CONSTRUCTION)

AD=AD (COMMON)

triangle BAD (congruent) triangle CAD (BY SAS)

therefore; <ABD=<ACD (CPCT)

SO, <B=<C

THAT'S THE ANSWER YOU NEED...

Answer 2

Answer:

Proof: we are given an isosceles triangle ABC in which AB=AC . WE need to prove that <A = <C

Let us draw the bisector of <A and let D be the point of intersection of this bisector of <A and BC (SEE FIGURE)

In triangle BAD and triangle CAD,

AB=AC (GIVEN)

<BAD=<CAD (BY CONSTRUCTION)

AD=AD (COMMON)

triangle BAD (congruent) triangle CAD (BY SAS)

therefore; <ABD=<ACD (CPCT)

SO, <B=<C

Step-by-step explanation:

Proof: we are given an isosceles triangle ABC in which AB=AC . WE need to prove that <A = <C

Let us draw the bisector of <A and let D be the point of intersection of this bisector of <A and BC (SEE FIGURE)

In triangle BAD and triangle CAD,

AB=AC (GIVEN)

<BAD=<CAD (BY CONSTRUCTION)

AD=AD (COMMON)

triangle BAD (congruent) triangle CAD (BY SAS)

therefore; <ABD=<ACD (CPCT)

SO, <B=<C