Math, asked by Darshananand210, 10 months ago

Show that an unbounded family of continuous functions on a closed and bounded interval [a,b] must contain a sequence \{f_n\} which has no uniformly convergent sub-sequence, i.E., the existence of a uniform bound is a necessary condition for the pre-compactness.

Answers

Answered by Anonymous
4

Answer:

In the mathematical field of analysis, uniform convergence is a mode of convergence of functions stronger than pointwise convergence. A sequence of functions {\displaystyle (f_{n})}(f_{n}) converges uniformly to a limiting function {\displaystyle f}f on a set {\displaystyle E}E if, given any arbitrarily small positive number {\displaystyle \epsilon }\epsilon , a number {\displaystyle N}N can be found such that each of the functions {\displaystyle f_{N},f_{N+1},f_{N+2},\ldots }{\displaystyle f_{N},f_{N+1},f_{N+2},\ldots } differ from {\displaystyle f}f by no more than {\displaystyle \epsilon }\epsilon at every point {\displaystyle x}x in {\displaystyle E}E. Described in an informal way, if {\displaystyle f_{n}}f_{n} converges to {\displaystyle f}f uniformly, then the rate at which {\displaystyle f_{n}(x)}f_{n}(x) approaches {\displaystyle f(x)}f(x) is "uniform" throughout its domain in the following sense: in order to determine how large {\displaystyle n}n needs to be to guarantee that {\displaystyle f_{n}(x)}f_{n}(x) falls within a certain distance {\displaystyle \epsilon }\epsilon of {\displaystyle f(x)}f(x), we do not need to know the value of {\displaystyle x\in E}x\in E in question — there is a single value of {\displaystyle N=N(\epsilon )}{\displaystyle N=N(\epsilon )} independent of {\displaystyle x}x, such that choosing {\displaystyle n}n to be larger than {\displaystyle N}N will suffice.

The difference between uniform convergence and pointwise convergence was not fully appreciated early in the history of calculus, leading to instances of faulty reasoning. The concept, which was first formalized by Karl Weierstrass, is important because several properties of the functions {\displaystyle f_{n}}f_{n}, such as continuity, Riemann integrability, and, with additional hypotheses, differentiability, are transferred to the limit {\displaystyle f}f if the convergence is uniform, but not necessarily if the convergence is not uniform.

Similar questions