show that angels of an equilateral triangle are 60* each.
Answers
Answered by
13
In equilateral triangle all sides are equal..
AB + BC + CD = 180°
AB + AB + AB = 180°
3AB =180°
AB=180°/3
AB= 60°
Hence, proved......
pless mark brainliest..
AB + BC + CD = 180°
AB + AB + AB = 180°
3AB =180°
AB=180°/3
AB= 60°
Hence, proved......
pless mark brainliest..
Answered by
6
hey dear here's the answer
since it is an equilateral triangle so all the sides are equal
so let the three angles be x
x+x+x= 180°
=> 3x =180°
=> x = 180/3 = 60°
hence proved
hope it helps to
since it is an equilateral triangle so all the sides are equal
so let the three angles be x
x+x+x= 180°
=> 3x =180°
=> x = 180/3 = 60°
hence proved
hope it helps to
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