Question

show that angle in the semi circle is a right triangle​

Answer 1

ANSWER :-

Label the diameter endpoints A and B, the top point C and the middle of the circle M.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.Angle MAC = ACM = Alpha because the left subtriangle is iscosceles because the opposite sides AM and CM are both radii.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.Angle MAC = ACM = Alpha because the left subtriangle is iscosceles because the opposite sides AM and CM are both radii.Angle MBC = BCM = Beta because the right subtriangle is iscosceles because the opposite sides BM and CM are both radii.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.Angle MAC = ACM = Alpha because the left subtriangle is iscosceles because the opposite sides AM and CM are both radii.Angle MBC = BCM = Beta because the right subtriangle is iscosceles because the opposite sides BM and CM are both radii.Add up the angles at A, B and C.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.Angle MAC = ACM = Alpha because the left subtriangle is iscosceles because the opposite sides AM and CM are both radii.Angle MBC = BCM = Beta because the right subtriangle is iscosceles because the opposite sides BM and CM are both radii.Add up the angles at A, B and C.This gives 2 * Alpha + 2 * Beta, which sum to 180° because ABC is a triangle.

Label the diameter endpoints A and B, the top point C and the middle of the circle M.Label the acute angles at A and B Alpha and Beta.Draw a radius 'r' from the (right) angle point C to the middle M.Angle MAC = ACM = Alpha because the left subtriangle is iscosceles because the opposite sides AM and CM are both radii.Angle MBC = BCM = Beta because the right subtriangle is iscosceles because the opposite sides BM and CM are both radii.Add up the angles at A, B and C.This gives 2 * Alpha + 2 * Beta, which sum to 180° because ABC is a triangle.Halving this gives Alpha + Beta (= the angle ACB) = 90°

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