show that angle of an equilateral triangle are 60° each
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Hey mate!
Here is your answer
Let us consider,
ABC be an equilateral triangle
BC = AC = AB (Length of all sides is same)
∠A = ∠B = ∠C (Sides opposite to the equal angles are equal)
Also,
∠A + ∠B + ∠C = 180° ( Sum of interior angles of a triangle is 180°)
3∠A = 180°
∠A = 60°
Therefore,
∠A = ∠B = ∠C = 60°
Thus,
The angles of an equilateral triangle are 60° each
Hope it helps
Here is your answer
Let us consider,
ABC be an equilateral triangle
BC = AC = AB (Length of all sides is same)
∠A = ∠B = ∠C (Sides opposite to the equal angles are equal)
Also,
∠A + ∠B + ∠C = 180° ( Sum of interior angles of a triangle is 180°)
3∠A = 180°
∠A = 60°
Therefore,
∠A = ∠B = ∠C = 60°
Thus,
The angles of an equilateral triangle are 60° each
Hope it helps
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Answered by
4
Hello mate ^_^
____________________________/\_
Solution:
∆ABC is equilateral which means that
AB=BC=AC.
AB=AC means that ∠B=∠C (In triangle, angles opposite to equal sides are equal) .....(1)
AB=BC means that ∠A=∠C (In triangle, angles opposite to equal sides are equal) ...... (2)
From (1) and (2), we can say that
∠A=∠B=∠C .........(3)
Also, ∠A+∠B+∠C=180° (Angle sum property of triangle)
Putting (3) in the above equation, we get
∠A+∠A+∠A=180°
⇒3∠A=180°
⇒∠A=180/3=60° .......(4)
From (3) and (4), we can say that
∠A=∠B=∠C=60°
hope, this will help you.
Thank you______❤
_____________________________❤
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