Show that angle of friction is equal to angle of repose for a rough inclined plane.
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) Force acting along the inclined plane in downward direction - mg sinθ . This component is resposible for downward motion . (2) The component mg cosθ , which is balaneced by normal reaction . Hence tangent of angle of angle of repose (tanθ) is equal to coeffiecient of friction (fk) between the bodies .
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