Math, asked by karunyapaul, 6 months ago

show that any group of order 17 is cyclic​

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Answered by ItzStrawBerry
2

Show that G is cyclic. If we call H,M,N to the unique 7-Sylow, 11-Sylow and 17-Sylow subgroups respectively, then H,M,N⊲G. ... Each of these groups is cyclic so Z7×Z11×Z17 is cyclic as well.

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