show that any number 6^n where n € N can never end with the digit zero
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6ⁿ cannot end with digit zero because any Digit wants to end with zero it contains 5 as a factor but the
factor of 6ⁿ = 2ⁿX3ⁿ doesn't have 5 so it can't end with zero at any value of “n”
factor of 6ⁿ = 2ⁿX3ⁿ doesn't have 5 so it can't end with zero at any value of “n”
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