Show that any number of the form 3n , n ∈ N can never end with the digit 0.
pls solve it ASAP
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Step-by-step explanation:
Sol -
if 3n end with 0 then it must have 5 as a factor
but 3n show that it has neither 5 and 2 as a prime factor of 3n
also we know from the fundamental theorem of arithmetic that the prime factorisation of each number is unique
so 5 is not a doctor of 3n
hence 3n can never end with the digital 0
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