Show that any number of the form 4^n , n ϵ N can never end with the digit 0.
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Answer:
4^n can not end with digit 0
Step-by-step explanation:
4^n
if n = 0
then 4^0 = 1
4^odd number ends with 4
4^(2n+1) ends with 4
4^1 = 4 ,
4^3 = 64
4^5 = 1024
4^even number ends with 6
4^2n end with 6
4^2 = 16
4^4 = 256
4^6 = 4096
so 4^n can end with digit 1 , 4 or 6 only so
4^n can not end with digit 0
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