Math, asked by inzela837, 1 year ago

Show that any number of the form 4^n , n ϵ N can never end with the digit 0.

Answers

Answered by amitnrw
5

Answer:

4^n can not end with digit 0

Step-by-step explanation:

4^n

if n = 0

then 4^0 = 1

4^odd number ends with 4

4^(2n+1) ends with 4

4^1 = 4 ,  

4^3 = 64  

4^5 = 1024

4^even number ends with  6

4^2n end with 6

4^2 = 16

4^4 = 256

4^6 =  4096

so 4^n can end with digit 1 , 4 or 6 only so

4^n can not end with digit 0

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