show that any number of the form (6)^n can never ends with the digit 0.
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6ⁿ = 2ⁿ × 3ⁿ
We cannot say that any number in form of 6ⁿ can end with the digit 0 as it lacks (atleast) the factor 5. The minimum requirement for any number in form of 6ⁿ to end with 0 is having atleast 2 and 5 as factors.
∴ Any number in form of 6ⁿ can never end with the digit 0.
(Question for you:-
- Show that any number in form of 10ⁿ can end with the digit 0.)
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