Question

show that any number of the form 6 to the power n where nen can never end with the digit 0.

Answer 1

6 has factors as 2 and 3

so 6 ⁿ = 2ⁿ * 3ⁿ

but for a number to end with 10 it should have 2 and 5 as factors

so, 6ⁿ can never end with 0

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Answer 2

Hello,

6 has two factors i.e 2 and 3

so, 6^n=2^n×3^n

but for any number to end with 0 it should have 2 and 5 as factors.

hence,6^n can never end with 0.

hope it helps you..