Question

show that any odd integer is of the form of 4m+1 or 4m+3 where m is some integer​

Answer 1

Step-by-step explanation:

Let m be a integer and let it be divided by 4

Then

0>=m>4

possibilities:-

4m+0

4m+1

4m+2

4m+3

4m+4

Here odd integers are in form of 4m+1 and 4m+3 and rest are positive

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Answer 2

Answer:

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Step-by-step explanation:

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