Question

Show that any odd positive integer is of the form 4m+1 or 4m+3 where m is some integer​

Answer 1

Answer:

So we have, s = 4m or s = 4m + 1 or s = 4m + 2 or s = 4m + 3. Here, 4m, 4m + 2 are multiples of 2, which revert even values to s. Again, s = 4m + 1 or s = 4m + 3 are odd values of s. Thus, any positive odd integer is of the form (4m + 1) or (4m + 3) where s is any odd integer.

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