Question

show that any positive add integer is of the form of 2m+1 and even is of the form 2 m​

Answer 1

Answer:

let 'a' be any positive integer and b=2

By euclid's division algorithm

a=bq+r 0≤ra=2q+r 0≤r<2

(i.e) r =0,1

r=0 , a=2q+0=> a=2q

r=1, a=2q+1

if a is the form of 2m then 'a' is an even integer and positive odd integer is of the form 2m+1

hope this helps u ~~~