Show that any positive integer is of the form 6m 6m+2 6m+4
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Answer:
a=bq+r
let b=6
0<r<6
where (r=0,1,2,3,4,5)
at r=0
a=6q+0
a=6q
squaring on both sides
(a) power 2 =(6q) power 2
a=36(q)power 2
a=36m (q power 2 =m)
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