Math, asked by seeedaya, 1 year ago

Show that any positive integer is of the form 6q+1 or 6q+3 or 6q+5

Answers

Answered by kashishbaesla
6

Here is the answer but u plz do check ur question once ... Hope it helps .. mark as btainliest ...

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kashishbaesla: Plz mark as brainliest ..
Answered by AdorableAstronaut
14

 \huge{\underline{ \underline \blue{ \sf{Detailed \: Answer}}}}

Any number divided can be written in the form of a = bq + r

Where,

  • a = Dividend

  • b = Divisor

  • q = Quotient

  • r = Remainder

According to the question, our equation will be a = 6q + r ; where r = 0, 1, 2, 3, 4, 5.

So when r = 0 ; The equation will be a = 6q + 0 = 6q

When r = 1 ; a = 6q + 1

When r = 2 ; a = 6q + 2

When r = 3 ; a = 6q + 3

When r = 4 ; a = 6q + 4

When r = 5 ; a = 6q + 5

In the question, it's already given that the integers should be written in the form of 6q + 1, 6q + 3 and 6q + 5.

Cause the rest numbers are even, and are divisible by 2.

So the required answer =

  • a = 6q + 1

  • a = 6q + 3

  • a = 6q + 5
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