Show that any positive integer is of the form 6q+1 or 6q+3 or 6q+5
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Any number divided can be written in the form of a = bq + r
Where,
- a = Dividend
- b = Divisor
- q = Quotient
- r = Remainder
According to the question, our equation will be a = 6q + r ; where r = 0, 1, 2, 3, 4, 5.
So when r = 0 ; The equation will be a = 6q + 0 = 6q
When r = 1 ; a = 6q + 1
When r = 2 ; a = 6q + 2
When r = 3 ; a = 6q + 3
When r = 4 ; a = 6q + 4
When r = 5 ; a = 6q + 5
In the question, it's already given that the integers should be written in the form of 6q + 1, 6q + 3 and 6q + 5.
Cause the rest numbers are even, and are divisible by 2.
So the required answer =
- a = 6q + 1
- a = 6q + 3
- a = 6q + 5
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