Show that any positive integer is on the form (4m+1)and (4m+3)for some integer m
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Let a be positive integer and b be 4
a = bq +r
r = 0 , 1 , 2 , 3
0 less than and equal to 4
a = bq +r
4q + o
4q
2(2q)
4q + 1
4m + 1
4q + 2
2(2q+1)
4q + 3
4m + 3
Since every positive integer is in the 4m +1 and 4m + 3
Step-by-step explanation:
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