Show that any positive odd integer can be written in the form 6m + 1, 6m + 3 or 6m + 5 where
m is a positive integer
Answers
Answer:
Step-by-step explanation:
Let n be a given positive odd integer.
On dividing n by 6 , let m be the Quotient and r be the remainder.
Then, by Euclid division lemma, we have
Dividend = Divisor × Quotient + Remainder
n = 6m + r. where r = 0 , 1 ,2 , 3 ,4 ,5
n= 6m + 0 = 6m. [ r =0]
n = 6m + 1 = 6m+1 [ r = 1 ]
n = 6m +2 = 6m +2 [ r = 2 ]
n = 6m +3 = 6m+3 [ r = 3 ]
n = 6m +4 = 6m+4 [ r = 4 ]
n = 6m+5 = 6m+5 [ r = 5 ]
N = 6m , (6m +2) , (6m+4) is even value of n.
Therefore,
when n is odd , it is in the form of (6m+1) , (6m+3) , (6m+5) for some integer m.
HOPE IT WILL HELP YOU.....
Step-by-step explanation:
Let n be a given positive odd integer.
On dividing n by 6 , let m be the Quotient and r be the remainder.
Then, by Euclid division lemma, we have
Dividend = Divisor × Quotient + Remainder
n = 6m + r. where r = 0 , 1 ,2 , 3 ,4 ,5
n= 6m + 0 = 6m. [ r =0]
n = 6m + 1 = 6m+1 [ r = 1 ]
n = 6m +2 = 6m +2 [ r = 2 ]
n = 6m +3 = 6m+3 [ r = 3 ]
n = 6m +4 = 6m+4 [ r = 4 ]
n = 6m+5 = 6m+5 [ r = 5 ]
N = 6m , (6m +2) , (6m+4) is even value of n.
Therefore,
when n is odd , it is in the form of (6m+1) , (6m+3) , (6m+5) for some integer m.