Question

show that any positive odd integer is in the form of 6q+1 or 6q+3,6q+5,where q is some integer

Answer 1

1. 6q = 2*3q - even
2. 6q+1 = 2(3q + 1)-odd
3. 6q+2 = 2(3q +2)-even
4. 6q+3= 2(3q+2) +1-odd
5. 6q+4= 2(3q+3)+1-even
6. 6q+5= 2(3q+4)+1-odd                          therefore 6q+1, 6q+3,6q+5 are odd integers......           hope it helps u thnk u......

Answer 2

1. 6q = 2*3q - even
2. 6q+1 = 2(3q + 1)-odd
3. 6q+2 = 2(3q +2)-even
4. 6q+3= 2(3q+2) +1-odd
5. 6q+4= 2(3q+3)+1-even
6. 6q+5= 2(3q+4)+1-odd                          therefore 6q+1, 6q+3,6q+5 are odd integers......           hope it helps u thnk u......