show that any positive odd integer is of the form 3m or 3m+1 or 3m +2, where ‘m’ is some integer
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16
Answer:
case 1 if m is even integer then 3m is even but 3m+1 is odd and 3m+2 is even
case 2 when m is odd integer
the 3m is odd 3m+1 is even and 3m+2 is odd
Answered by
31
Step-by-step explanation:
let x be any integer
now when x is divided by 3, there are three possibilities
1. the integer is divisible by 3
i.e. x = 3m
2. the integer is not divisible by 3 and the remainder is 1
i.e. x = 3m +. 1
3. the integer is not divisible by 3 and the remainder is 2.
now x= 3m is even for even m and odd for odd m.
3m+1 is always odd for all m
3m+2 is even for even m and odd for odd m.
thus any integer can be represented by the form mentioned at 1,2 and 3 above so can odd integer be
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