SHOW THAT ANY POSITIVE ODD INTEGER IS OF THE FORM 4 Q +1 OR 4Q+3 . WHERE Q IS SOME INTEGER ??
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Let us take a as any positive integer and b = 4.
By applying Euclid's Divisio Lemms, we get
a = bq + r (r is remainder and r = 0,1,2,3, 0 <= r < b, q>=0)
Therefore, the total possible forms = 4q + 0, 4q + 1, 4q + 2, 4q + 3.
Now,
(1)
= > 4Q + 0 = (It is divisible by 2 - Even number).
(2)
= > 4Q + 1 = (1 is not divisible by 2 - Odd number)
(3)
4Q + 2 = (2 is divisible by 2 - Even number)
(4)
4Q + 3 = (3 is not divisible by 2 - Odd number)
Therefore,
4Q + 1, 4Q + 3 are the positive odd integers.
Hope this helps!
By applying Euclid's Divisio Lemms, we get
a = bq + r (r is remainder and r = 0,1,2,3, 0 <= r < b, q>=0)
Therefore, the total possible forms = 4q + 0, 4q + 1, 4q + 2, 4q + 3.
Now,
(1)
= > 4Q + 0 = (It is divisible by 2 - Even number).
(2)
= > 4Q + 1 = (1 is not divisible by 2 - Odd number)
(3)
4Q + 2 = (2 is divisible by 2 - Even number)
(4)
4Q + 3 = (3 is not divisible by 2 - Odd number)
Therefore,
4Q + 1, 4Q + 3 are the positive odd integers.
Hope this helps!
siddhartharao77:
:-)
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