Question

show that any positive odd integer is of the form 4m+1 or 4m+3 where m is some integer ​

Answer 1

Answer:

Step-by-step explanation:

here is answer

let a be any positive integer

then

b=8

0≤r<b

0≤r<4

r=0,1,2, 3

i am taking q instead of m

case 1.

r=0

a=bq+r

4q+0

4q

case 2.

r=1

a=bq+r

4q+1

case 3.

r=2

4q+2

case4.

r=3

4q+3

Answer 2

Answer:

given in the picture

let a be any positive integer