Question

Show that any positive odd integer is of the form (6m+1)or(6m+3) or(6m+5) where m is some integer
please give me answer urgent

Answer 1

Any even number has is multiple of 2.
If u multiply any integer with 2 .. no will become even number
Ex = 2×3= 6 (even )
Ex = 4×2=8(even number )

6m = 3×2m
2m is an integer number ..
If you multiply it any odd number with even number you will get even number
Ex. 5×4= 20 (even )
6m is a even number
If you add an even number and an odd number you will get always odd number
5+6=11 (odd)
So
6m+1
6m+3
6m+5
Always be an odd number