Question

show that any positive odd integer is of the form 6q+1,6q+3,6q+5, where a is some integer

Answer 1

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Answer 2

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let a be any positive integer

then

b= 6

a= bq+r

0≤r<b

0≤r<6

r= 0,1,2,3,4,5

case 1.

r=0

a= bq+r

6q+0

6q

case 2.

r=1

a= 6q+1

6q+1

case3.

r=2

a=6q+2

case 4.

r=3

a=6q+3

case 5

r=4

a=6q+4

case 6..

r=5

a=6q+5

hence from above it is proved that any positive integer is of the form 6q, 6q+1,6q+2,6q+3,6q+4 and 6q+5and

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