Show that any positive odd integer is of the form 6q+1, 6q+3 or 6q+5, where q is some integer.
Answers
Answered by
7
Answer:
Step-by-step explanation:
a= bq+r where a is an odd positive integer
Where 0 <=r <b
Let b=6
Then a = 6q ,6q+1,6q+2,6q+3,6q+4,6q+5
But 6q,6q+2,6q+4 are even so
a= 6q+1, 6q+3 ,6q+5
mohan185:
totally correct bro but you not prove that even numbers
Answered by
4
Heya beautiful
Here is your answer
Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.
according to Euclid's division lemma
a=bq+r
a=6q+r
where , a=0,1,2,3,4,5
then,
a=6q
or
a=6q+1
or
a=6q+2
or
a=6q+3
or
a=6q+4
or
a=6q+5
but here,
a=6q+1 & a=6q+3 & a=6q+5 are odd.
Thanks mark me brainest
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