Show that any positive odd integer is of the form 6q+1, or 69 +3, or 6q +5, where q is
some integer.
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Answer:
The below is ur answer
Step-by-step explanation:
Let a be any positive integer and b = 6.
Then, by Euclid’s algorithm, a = 6q + r, where 0≤r<6 ,
r = 0, 1, 2, 3, 4, 5
If r = 0,
a = 6q + r
= 6q + 0
= 6q
= 2 * 3q
If r = 1,
a = 6q + 1
If r = 2,
a = 6q + 2
= 2 ( 3q + 1)
If r = 3,
a = 6q + 3
=3 ( 2q + 1 )
If r = 4,
a = 6q + 4
=2 (3q + 2)
If r = 5,
a = 6q + 5
2 is factor of all positive integers
6q , 6q + 2 , 6q + 4 are even numbers
Hence 6q + 1 , 6q + 3 and 6q + 5 are positive odd integers
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