Show that any positive odd integer is of the form 6q+1 or 6q+3 or 6q+5 ,where a is some integet
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Euclid division lemma:
two positive integers “a” and “b”, then there exists unique integers “q” and “r” such that which satisfies the condition a = bq + r where 0 ≤ r ≤ b.
Step-by-step explanation:
a=6q+1
where b=6; 0 ≤ r ≤ 6
The possible remainders are 0,1,2,3,4,5
a=6q+0=6q
a=6q+1
a=6q+2
a=6q+3
a=6q+4
a=6q+5
where q is quotient.....
By the problem a is odd integer.....
therefore, a cannot be 6q,6q+2,6q+4......
Hence, Any odd integer is of the form 6q+1 or 6q+3 or 6q+5......
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