Math, asked by ronakpatel2599, 6 months ago

Show that any positive odd integer is of the form 6q + 1, or 6q + 3, or 6q + 5, where q is some integer​

Answers

Answered by akshat12342
0

Answer:

not understood the question

Answered by MysteriousAryan
6

Answer:

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Let 'a' be any positive integer and b=6

Apply Euclid division lemma to A and B

a = 6q + r \: \:  \:  \:  where \: 0   \leqslant r < 6

r=0,1,2,3,4,5

a=6q,6q+1,6q+2,6q+3,6q+4,6q+5

and. a is positive odd integer

a≠6q. or a≠ 6q+2 or a≠6q+4

And. a=6q+1 ,a=6q+3 , a=6q+5

Hence proved

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