Question

Show that any positive odd integer is of the form 6q+1, or 6q+3. or 6q+5. where q is
some integer.​

Answer 1

$answer$

Let a be a given integer.

On dividing a by 6 , we get q as the quotient and r as the remainder such that

=>a = 6q + r, r = 0,1,2,3,4,5

when r=0

=>a = 6q,even no

when r=1

=>a = 6q + 1, odd no

when r=2

=>a = 6q + 2, even no

when r = 3

=>a=6q + 3,odd no

when r=4

=>a=6q + 4,even no

when r=5,

=>a= 6q + 5 , odd no

Any positive odd integer is of the form 6q+1,6q+3 or 6q+5.

Answer 2

Answer:

q=0/6

Step-by-step explanation:

6q+1=6(0/6)+1

=0+1

=1

6q+1=6(0/6)+3

=0+3

=3

6q+5=6(0/6)+5

=0+5

=5