Question

show that any positive odd integer of the form 6q + 1 or 6q + 3 or 6q + 5 Where u q is some integer​

Answer 1

Answer:

The answer has been given in above attachment

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Answer 2

Answer:

let n is a positive integer and n is divided by 6

n =6 q + r

(r is less than 6)

n= 6 q+1 = odd number

n= 6 q+ 2 = 2(3q+1)

n =6 q+3 =odd number

n =6 q+4

n =6 Q+5=odd number

so here odd number = 6q +1,, 6q+3,,6q+5

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