Question

show that any positive odd integers is of the form 6q + 1 or 6q + 3 or 6Q + 5 Where Q is some integer ​

Answer 1

Answer:

a=bq+r

r=0,1,2,3,4,5

now substitute the values u will get the answer

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Answer 2

Answer:

possible reminders =1,2,3,4,5

a=bq+r

a=6q+1=6q+1=2n+1=odd

a=6q+2=2(3q+1)=2n=even

a=6q+3=2(3q+1)+1+2+1=odd

a=6q+4=2(3q+2)=2n=even

a=6q+5=2(3q+2)+1=odd

therefore.6a+1.6a+3.6a+5 are postive odd