Question

show that any positive odd is of the form 6q+1,or6q+3,or6q+5 where q is some integer​

Answer 1

Answer:

let a be any positive integer and b be any divisor

b

Step-by-step explanation:

b=6

as per EDL : a =bq +r

if r=0

then a=6q +0 =6q (even)

if r=1 then,

a=6q+1 (odd)

if r=2 then,

a=6q +2 (even)

if r=3 then,

a=6q +3 (odd)

if r=4 then,

a=6q + 4 (even)

if r= 5 then,

a=6q + 5 (odd)

so from above outcomes we conclude that every positive odd number is in form of 6q +1 ,6q+3,6q+ 5