Math, asked by patelroshanij, 11 months ago

show that any positive odd number is of the form 6q+3, 6q+1, 6q+5. where q is some integer​

Answers

Answered by reneshking
0

Answer:

Step-by-step explanation:as we know from Euclid's division lemma that a=bq+r .So here b=6 and that's why r will be equal or bigger than 0 and smaller than 6 . So we get a=6q+1....6q+5. As 6q+2 and 6q+4 are divisible by 2 we find that any positive odd integer is of the form 6q+1, 6q+3 or 6q+5. Hence proved

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